Thursday, 14 April 2016

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Quant Quiz For SSC (advance Maths) part-1

Hello philic's,
Many aspirants told us to start daily quiz on the advanced section of maths for ssc exam, keeping their Dream on mind, we started this section, we'll update it on daily basis. As SSC CGL exam is coming near, many of candidates are studying very hard for this exam and want to crack this exam very seriously. Many of candidates understand this thing that QUANTITATIVE APTITUDE Section plays a pivotal role in deciding the cut-off for candidates giving this exam especially the ADVANCED MATHS portion.
Quant Quiz For SSC (advance Maths) part-1

1.    What will be the length of the diagonal of that square plot whose area is equal to the area of a rectangular port of length 45 meters and breadth 40 meters?
(a) 42.5 meters                 
(b) 60 meters
(c) Data inadequate           
(d) 45 meters


2.    The length of a rectangle is 20% more than its breadth. What will be the ratio of the area of a rectangle to that of a square whose side is equal to the breadth of the rectangle?
(a) 2:1                                
(b) 6:5
(c) 3:4                                
(d) Data inadequate

3.    If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
(a) 40 cm                          
(b) 50 cm
(c) 60 cm                          
(d) 30 cm

4.    The base of triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
(a) 200 m                          
(b) 275 m
(c) 300 m                          
(d) 600 m

5.    The difference between two parallel sides of a trapezium is 4 cm. The perpendicular distance between them is 19 cm. If the area of the trapezium is 475 cm2, find the lengths of the parallel sides.
(a) 27 cm & 23 cm           
(b) 22 cm & 25cm
(c) 20 cm & 27 cm           
(d) 23 cm & 25 cm

6.  A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
A.3.6kg
B.3.696kg
C.36kg
D.36.9kg

7.  A right triangle with sides 3 cm, 4 cm and 5 cm is rotated about the side of 3 cm to form a cone. The volume of the cone so formed is
A.12piecm^3
B.15pie cm^3
C.16pie cm^3
D.20pie cm^3

8.  The surface area of a sphere is same as the curved surface area of a right circular cylinder whose height and diameter are 12 cm each. The radius of the sphere is
A.3cm
B.4cm
C.6cm
D.8 cm

9.  Five equal cubes, each of side 5 cm, are placed adjacent to each other. The volume of the new solid formed will be
A.125cm^3
B.625cm^3
C.15525cm^3
D.1225cm^3

10.   An iron cubes of side 10 cm is hammered into a rectangular sheet of thickness 0.5 cm. If the sides of the sheet are in the ratio 1 : 5 the sides are
A.10cm,50cm
B.20cm,100cm
C.40cm,200cm
D.None of these



Answer with complete solution:
1.   (b) 
Area= (45* 40) m= 1800 m2,
(Diagonal)2/2= 1800,
Diagonal = 60m

2.  (b)
  Let breadth be x meters. Then length= 120% of x = 120/100 x= 6x/5 m
Therefore, the required ratio= {(6x/5)*x*x}/x*x = 6:5

3.  (b) 
Let x and y be the length and breadth of the rectangle respectively.
Then, x ­- 4 =y + 3 or x – y = 7 ………..(i)
Area of rectangle = x*y,
Area of square = (x-4) * (y+3)
So, (x-4) * (y+3)= x*y,
or 3x – 4y = 12……………………………….(ii)
Solving eq (i) & (ii) x= 16 and y = 9
Therefore perimeter of rectangle = 2(x+ y)= 2(16+9)= 50 cm

4.  (c) 
 Area of the field = Total cost/ Rate = 333.18/ 24.68 hectares = 13.5 hectares
= (13.5 * 1000) m= 135000 m2
Let altitude = x meters and base = 3x meters.
Then, 1/2 * 3x * x = 135000
x2 = 90000
x= 300 m

5.   (a) 
Let the two parallel sides of the trapezium be a cm and b cm,
Then, a-b = 4……………………….(i)
And, 1/2 *(a+b)*19 = 475
(a+b) = (475*2)/19 =50…………(ii)
Solving eq(i)& (ii) a= 27 cm and b = 23 cm


6. External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron    =(22/7×(42)-(32)×21)cm^3
= (22/7×7 ×1×21)cm^3
= 462 cm^3.

7.(a) 

8. 4?R^2= 2?6x12
R^2 = (6x12/2)= 36
R = 6 cm. 

9.The new solid formed is a cuboid of length 25 cm, breadth 5 cm and height 5 cm
Volume = (25x5x5)cm^3
‹=›625cm^3

10.Let the sides of the sheet be x and 5x.
Then,volume of the sheet= volume of the cube
‹=› x × 5x ×1/2
‹=› 10×10×10
‹=› 5x^2= 2000
‹=› x^2= 400
‹=› x = 20.
The sides are 20 cm and 100 cm.






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